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5m^2+8m=15
We move all terms to the left:
5m^2+8m-(15)=0
a = 5; b = 8; c = -15;
Δ = b2-4ac
Δ = 82-4·5·(-15)
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{91}}{2*5}=\frac{-8-2\sqrt{91}}{10} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{91}}{2*5}=\frac{-8+2\sqrt{91}}{10} $
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